Silver Valence Electrons

How many valence electrons are there in silver? 3

Very simple and uninteresting answer: I forgot a line in the redundant red head table IC. SS is 2,8,8,18,11 to get 47. You may be looking for 11 answers.

A little old but very vague answer:

It depends on the valence of w. We ask a question, you probably have a very simple algorithm to answer it. Like all these algorithms, it completely loses its basic conceptual point and is much more interesting.

Long answer that really solves the real problem:

The general formula for finding valence electrons is #valence e = number of groups. It's not that useful. Most people use pattern 118 in the table for group numbers, which means that carbon is in group 14 and does not have 14 valence electrons. Using the old Roman numerical indicator, Fe Co and Ni * all * are in group VIII and obviously there can be no number of electrons with the same valence as different columns. So that's not a good thing.

Or you could write electron configuration, and valence electrons are important quantum numbers (which are almost consistent with Bohr's theory). C is (1s) 2 (2s) 2 (2p) 2, so n = 2 s has four e's, so four valences are electrons. Na is (1s) 2 (2s) 2 (2p) 6 (3s) 1, ie, and in n = 3 s, ie valence electrons.

Table s and p blocks are good for main group elements. A small hint, resulting in #valencia e = group number (block s) or group number Â € Â "10 (block p).

But this method is a train wreck for dblock or fblock.

The problem with explaining a stereotype is that it loses its meaning. Valence is involved in electron chemistry. They can be lost, needed, or shared to form bonds, or properties can be changed just by sitting on the verbal limit of a connection, but the valence number or electron is what defines chemistry, so A table that serves as a map of the order of the valence electrons. Is a very useful tool. And D-block elements use their electrons for chemistry.

It is a bit misleading to say that Ag has only one valence electron because it has only one electron at n = 5s. One argument may be that this is a reasonable explanation for groups 11 and 12, this argument does not extend well to iron, molybdenum or vivo. (Or actually copper or gold, for which the answer obtained by this method would probably be the same. Cu produces a lot of chemicals Cu (II) and the other 9 electrons are important for what happens. Gold produces a lot of Au (III). Tse elements always use their electrons to form harmonious bonds, bring them back to the nucleus and leave only electrons behind (usually lost) because Valence does not describe chemistry and therefore They lose their center.

Therefore, the best rule of thumb, in some cases, is subject to thematic disagreement as to what the word valence actually means:

sblock: highest value only n, valence eÃ - = group number

pblock: highest value only n, valence eÃ € Â "= group number Â - 10 (in 118)

Block D: Contains S and D electrons, valence eÃ - = group number

fblock: All s, d and f consist of electron plus or minus.

If you follow this, it will be Ag 11.

But many chemists are satisfied with 1, because silver is a chemical that contains only the outermost electrons in the ■■■■ cavity.

It depends on the valence of w.

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In response to the redheaded exaggeration, edit:

Your answer is * partially * correct, but incomplete because your chemistry teacher gave you only simple formulas, did not help you to understand what was really happening, or did the chemist actually valence Used the term

Yes, you are right, if we use your formula for 2n 2 electrons per s, then n = 3s has 18 electrons. (But why didn't he work on the next one? Why 2,8,18,18? 2n 2 should be 2,8,18,32, right?) The correctly scored answers on the questionnaire were too many.

I don't care about high school exams. I teach at university. I did real research with real transition metal compounds. Therefore, I cannot rely on simple formulas based on 100-year-old (and often incorrect) atomic structure models, and I cannot rely on Wikipedia as a source. To understand their chemistry in the real world, I really need to understand what is going on in these elements.

The problem with any algorithmic formula is that you enter numbers into the formula without understanding what they mean. The formula means that the element with n = 5 and n = 4 electrons can never contain n = 4 and valence electrons. This is not true.

A more efficient method is to examine the structure and patterns of table ic. Element number 37 contains rhodium in group 1. Formula 9 predicts valence electrons (2 + 8 + 18 + 9), which is incorrect. Rb has only one valence electron because it does not complete the sequence of ss. After capturing only 8 electrons n = 4, one electron goes to n = 5 s (2 + 8 + 18 + 8 + 1 or, according to my proposed model, 2 + 8 + 8 + 18 + 1), This is why Rb is in Group 1 with H Li Na K. It is wrong to assume that every n = 4 is filled with n = 5 and every n = 3 is filled with n = 4, but the structure of the table is not correct ic sws! (The same is true of Wikipedia).

My formula corresponds to the observed ic structure: 2,8,8,18,18 is the number of elements in the first five rows of the table.

1: 2 fills the elements, H and He, n = 1 s.

2: 8 elements, Li to Ni, fill n = 2.

Fill only 4 of the 3: 8 elements, Na to Ar, 9 ■■■■ n = 3.8 electrons instead of 18.

4:18 Elements. K and Ca first fill the ortho n = 4 with 2 electrons, then refill Scn to Zn and fill the remaining five orthos n = 3, then Ga to Kr fill the other 3 orthos n = 4.

5:18 Elements. Rb and Ba first fill n = 5 with two electrons, Ya to Cd fill five n = 4 with 10 electrons in one X, and the remaining three n = 5 are filled with 6 electrons.

When you pass the fifth, you find transition metals, where 5s electrons and 4d electrons need to be added to the valence calculation because they all affect the chemical behavior. Gr 6 has 6 valence electrons of Mo. (What number does your formula predict for element # 42? 2 + 8 + 18 + 14, then 14? Does that make sense? Does Wikipedia give you this answer?) 8 in ru is group 8 Ag is in group 11. It has eleven verbally accessible high energy electrons, divided into n = 4 and n = 5 ss. Wikipedia also reports the electron configuration of the neutral atoms of Ag: [Kr] (4d) 10 (5s) 1. In some compounds, 1 electron is used for chemistry and only 1 electron of n = 5 is lost. Gives or even shares some compounds. They break down into n = 4 s, and 11 external electrons affect chemistry and physics. Characteristics of Silver Compounds (How would you explain the presence of AgF2 when Ag has only one electron available for chemistry? W Explain the fact that Cu is usually [Cu] 2+ instead of [Cu] + In the form of, although the formula also only predicts the valence electron. Up to Cu?)

Then. As I said, the most complete and useful answer to this question is 1 or 11, depending on it. Most of the time, only one of them consists of an external electron. Sometimes we 11th chemists have to keep in mind that the algorithmic application of a simple formula will not always give a complete or useful answer as it does not reflect the correct understanding of the chemistry in these compounds or the actual answer. . The conceptual definition of what the word valence should mean.

Silver Valence Electron

This page can help you.

w I have many valence electrons, what is silver?

The silver atom number is 47. If we write the electron configuration of silver, we get 2, 8, 18, 18, 1. The valence electrons are in the outermost s, in this case the fifth s. As you can see, silver has 1 valence electron.

For example help = d

Postscript:

Stephen McNeil, my answer is correct. The atomic number of silver is 47: 2 + 8 + 18 + 18 + 1 = 47! Take a look at your computer ...

According to the 2n square principle, the third would have a capacity of 18 electrons instead of 8!

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That makes sense, Mr. McNeil, but I'm sure Polly is looking for simple, comprehensive chemistry answers that you shouldn't give. In modern chemistry, silver has 1 valence electron.

Silver Valence Electrons

Rocket 7 years ago, you said, so trust Wikipedia to confirm your answer, you don't know how many electrons went to SS and
AgNO3 is silver nitrate. Here, the value of money is +1.
Usually +1
I think 1 ... could be wrong.